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BITSAT 2017 Solved Chemistry Practice Paper Set-I

Hariom Singh

Birla Institute of Technology and Science Admission Test(BITSAT) is a computer-based admission test conducted by BITS. This year BITSAT will be held between 16th May to 30th May, 2017. The Chemistry section of BITSAT contains 40 questions.

Few random questions from the sample paper are given below:

Q1.      Which of the following statements regarding the entropy is not true?

            (a)  S(monoclinic) > S(rhombic)                                    (b)  C(diamond) > C(graphite)

            (c)  H2O(g) > H2O(l)                                                    (d) O3(g) > O2(g)

Sol.      At room temperature, C(graphite) is more stable than C(diamond)


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Q2.      Hydrogen bonding is maximum in

            (a)  Ethanol                  (b)  Diethyl ether         (c)  Ethyl chloride       (d) Ethyl amine

Sol.      Ethers and halides do not form H-bonding whereas oxygen being more electronegative forms excessive H-bonding.


Q3.      In the isoelectronic series K+, Cl-, S2-, Ca2+ the largest size is of

            (a)  K+                          (b)  Cl-                                 (c)  Ca2+                       (d) S2-

Sol.      In isoelectronic ions, lesser the nuclear charge, larger is the size.


Q4.      Hard water when passed through ion exchange resin containing RCOOH, becomes free from

            (a)  Cl- ions                 (b)   ions             (c)  H3O+ ions              (d) Ca2+ ions

Sol.      Cations are removed by ion exchanger containing RCOOH.


Q5.      The different layers in graphite are held together by

            (a)  Ionic bonding                                            (b)  Metallic bonding

            (c)  Covalent bonding                                     (d) vander Waal’s forces

Sol.      Graphite has two dimensional sheet like structure in which the various layers in graphite are held together by weak vander Waal’s forces and those layers can slide   

             over each other.


Q6.      A 0.6% solution of urea (M.W. = 60) would be isotonic with 

            (a)  0.1 M Glucose                                           (b)  0.1 M KCl

            (c)  0.6% Glucose solution                              (d) 0.6% KCl solution

Sol.      0.6% solution of urea corresponds to a molarity of 0.1 M.

            Hence it is isotonic with 0.1 M glucose


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