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JEE Main 2019: Normalisation of Marks

JEE Main, the most sought after engineering entrance exam will be conducted between Jan 6 and 20, 2019 in completely computer based test (CBT) mode. From this year, the National Testing Agency will conduct the Joint Entrance Exam (JEE) Main twice a year. The complete schedule for both the phases of JEE Main 2019 has been already declared by the exam conducting body (NTA).

JEE Main 2019 Schedule:

How to fill JEE Main application form 2019?

The candidates who will qualify JEE Main will be eligible for appearing in JEE Advanced 2019, which is the next level for admissions to Indian Institute of Technology (IITs). Only candidates who will qualify JEE Advanced 2019 will be shortlisted for final admissions to IITs. However, the successful candidates of JEE Main 2019 can take admission in different NITs, GFTIs and IIITs through JoSAA counselling.

The National Testing Agency (NTA) will calculate marks of qualified candidates based on a normalisation process to prepare the rank list for JEE Main 2019. In this article, we are going to explain you the complete normalisation process to be followed by the National Testing Agency.

 


Basic Terminologies:

Raw score:

The row score will be calculated by NTA on the basis of the marking scheme of the examination. For each correct answer marked by the candidates 4 marks will be added, while for each incorrect answer, 1 mark will be deducted from the total score.

Percentile Scores:

The percentile scores will be obtained by converting the raw marks into a scale ranging from 100 to 0 for each session of examinees.

The Percentile score will be the Normalized Score for the examination (instead of the raw marks of the candidate) and shall be used for preparation of the merit lists.

Note:- The Percentile Scores will be calculated up to 7 decimal places to avoid bunching effect and reduce ties.

Steps to be followed for getting JEE Main 2019 Normalised Score:

Step 1:

The row score of each candidate for each subject (Maths, Physics and Chemistry) will be calculated by the National Testing Agency.

Step 2:

The percentile scores for each of the subject and total percentile score will be calculated using the below formula:

Here, T1,M1, P1, C1 are the raw scores in Total, Mathematics, Physics, Chemistry of a candidate and T1P, M1P, P1P, C1P are the percentile scores of Total, Mathematics, Physics, Chemistry of that candidate.

Subjects to be used for normalization:

  1. Physics
  2. Mathematics
  3. Chemistry


Tie-breaking rules:

(a) Candidates obtaining higher Percentile Score in Mathematics will get higher rank.

(b) Candidates obtaining higher Percentile Score in Physics will get higher rank.

(c) Candidates obtaining higher Percentile Score in Chemistry will get higher rank.

(d) Candidates older in age will get higher rank.

JEE Main 2019 CBT; NTA practice centres will be turned into free coaching centres, Steps to register

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