Maharashtra Board Class 12 Chemistry Solved Question Paper 2018

Solving previous year question papers is considered to be the best practice to not only familiarising with the pattern of questions asked in board examinations but also to analyse your preparation level in an effective way.

In this article, we are providing the Maharashtra Board Class 12 Chemistry Solved Question Paper 2018. Solutions have been collated in the form of PDF which students may download to check the right criteria to write perfect exam and score high marks.

Key features of Maharashtra Board Class 12 Chemistry Solved Question Paper 2018 are

  • Simple and stepwise solutions are provided for each question
  • Appropriate concepts have been used in solutions
  • Chemical equations are written correctly

A few sample questions and their solutions are given below:

Q. Derive the relation between elevation of boiling point and molar mass of solute.


Elevation of boiling point (ΔTb) is directly proportional to molality of the solution (m).


Where w1 = Mass of a solvent in gram; w2 = Mass of a solute in gram; M2 = Molecular mass of the solute.

Q. State third law of thermodynamics. Give ‘two’ uses.


The third law of thermodynamics states that “The entropy of a perfect crystal at absolute zero temperature is exactly equal to zero.”

  • Third law of thermodynamics is applicable in following cases:
  • It helps in calculating thermodynamic properties
  • It is helpful in measuring chemical affinity.
  • It is used to determine the absolute entropy of any substance either in solid, liquid or gaseous state at any desired temperature.

Q. Define: a. Semipermeable membrane

b. Reference electrode


(a) Semipermeable membrane: It is a membrane which allows the solvent molecules, but not the solute molecules, to pass through it.

(b) Reference electrode: It is an electrode whose potential is arbitrarily taken as zero or is exactly known.

Q. What is the action of chlorine on:

a. CS2

b. Excess NH3


Action of chlorine on CS2

The reaction of carbon disulphide (CS2) with chlorine gas (Cl2) will form carbon tetrachloride (CCl4) and sulphur monochloride (S2Cl2). The reaction is as follows:

CS2 + 3Cl2 → CCl4 + S2Cl2

Action of chlorine on excess NH3

Chlorine gas (Cl2) reacts with excess ammonia to give ammonium chloride (NH4Cl) and Nitrogen gas. The reaction is as follows:

3Cl2 + 8NH3 → 6NH4Cl + N2

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Maharashtra Board Class 12 Chemistry Solved Question Paper 2018

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