NCERT Solutions for CBSE Class 12 Mathematics ‒ Chapter 2: Inverse Trigonometric Functions (Part V)

NCERT Solutions for CBSE Class 12th Mathematics, Chapter 2: Inverse Trigonometric Functions are available here. Here, you will get solutions of exercise 2.2 (from question number 11 to question number 15). The questions given in this exercise are based on basic properties of inverse trigonometric functions. These questions are important for CBSE Class 12 board exam 2018.

NCERT Solutions for CBSE Class 12th Maths, Chapter 2: Inverse Trigonometric Functions (Exercise 2.2) are given below

Question 11:

Solution 11:

Therefore, the value of expression is π/4.

CBSE Class 12 Maths Syllabus 2017 - 2018

Question 12:

cot (tan‒1a + cot‒1a)

Solution 12:

Therefore, cot (tan‒1a + cot‒1a) = 0

Question 13:


Solution 13:


Question 14:

If sin {sin‒1(1/5) + cos‒1(x)} =1, then find the value of x

Solution 14:

The value of x = 1/5.

Question 15:


Solution 15:

Therefore, the value of x = π/3.

Download NCERT Solutions for Class 12 Mathematics Chapter 2 - Inverse Trigonometric Functions in PDF Format

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