# NCERT Solutions for CBSE Class 12 Mathematics ‒ Chapter 2: Inverse Trigonometric Functions (Part VI)

NCERT Solutions for CBSE Class 12th Mathematics, Chapter 2: Inverse Trigonometric Functions are available here. Here, you will get solutions of exercise 2.2 (from question number 16 to question number 21). These questions are based on basic properties of inverse trigonometric functions. These questions are also important for CBSE Class 12 board exam 2018.

*NCERT Solutions for CBSE Class 12th Maths, Chapter 2: Inverse Trigonometric Functions (Exercise 2.2) are given below*

**Question 16:** sin^{‒1} (sin 2π/3)

**Solution 16:**

sin^{‒1} (sin 2π/3)

= sin^{‒1} [(sin π - 2π/3)]

= sin^{‒1} [sin (π/3)]

= π/3

**CBSE Class 12 Maths Syllabus 2017 - 2018**

**Question 17: **tan^{‒1 }(tan 3π/4)

**Solution 17:**

tan^{‒1 }(tan 3π/4)

= tan^{‒1 }[‒ tan (‒3π/4)]

= tan^{‒1 }[‒ tan (π ‒ π/4)]

= tan^{‒1 }[‒ tan (π/4)]

= tan^{‒1 }[ tan (‒π/4)]

= ‒π/4.

**Question 18:** tan [sin^{‒1} (3/5) + cot^{‒1} (3/2) ]

**Solution 18:**

**Question 19:** cos^{‒1} [cos (7π/6)] is equal to

(A) 7π/6

(B) 5π/6

(C) π/3

(D) π/6

**Solution 19:**

**Question 20:** sin [(π/3) ‒ sin^{‒1} (‒1/2)] is equal to

(A) 1/2

(B) 1/3

(C) 1/4

(D) 1

**Solution 20:**

**Question 21:** tan^{‒1 }√3 ‒ cot^{‒1} (‒√3) is equal to

(A) π

(B) ‒ π/2

(C) 0

(D) 2√3

**Solution 21:**