UPSEE: Important Questions and Study notes for Coordination Compounds

Because of the tough competition, engineering aspirants can’t miss any single topic during their preparation if they want to crack any engineering entrance examination. Around 25% of the questions have always been asked from Inorganic Chemistry in UPSEE/UPTU entrance examination.

The chapter ‘Coordination Compounds’ is one of the most important chapters in Inorganic Chemistry.  Students always find about 1-2 questions from this chapter in the examination.

In this article, students will get the revision notes of Coordination Compounds prepared by Subject Experts after the detailed analysis of previous years’ papers and latest syllabus of UPSEE/UPTU.

UPSEE/UPTU Chemistry Syllabus: 2017 - 2018

Students can study the following topics here:

1. Werner coordination compound theory,

2. Important terms in coordination compound,

3. Nomenclature of coordination compound,

4. Valence bond theory and

5. Crystal field theory

Important Concepts:

UPSEE: Important Questions and Study notes for Hydrocarbons

UPSEE: Important Questions & Study Notes for Bimolecules

Some solved questions are given below:

Question 1:

Which of the following is diamagnetic in nature?

(a) Co3+, octahedral complex with weak field ligand

(b) Co3+, octahedral complex with strong field ligand

(c) Co2+ in tetrahedral complex

(d) Co2+ in square planar complex

Solution 1:

In presence of strong field ligand, all the electrons present in 3d subshell of Co3+ ion, will pair up.

Hence due to the absence of any unpaired electron the complex is diamagnetic in nature.

Hence, the correct option is (b).

UPSEE: Important Questions and Preparation Tips – Periodic Classification & Periodicity in Properties

Question 2:

The compounds [Co(SO4)(NH3)5]Br and [Co(SO4)(NH3)5] Cl represent

(a) linkage isomerism                                      

(b) Ionisation isomerism

(c) coordination isomerism                             

(d) no isomerism

Solution 2:

Compounds having same molecular formula be different structural formula are known as isomers, [Co(SO4)2(NH3)5]Br and [Co(SO4)(NH3)5]Cl molecular formula. Hence, they are not isomers.

Hence, the correct option is (d).

UPSEE: Important Questions and Preparation Tips – Solid State

Question 3:

Hybridisation and shape of K3[Co(CO3)3] is:

(a) d2sp3and Octahedral

(b) sp3d2 and Octahedral

(c) dsp2 and square planar

(d) sp3 and tetrahedral

Solution 3:

Oxidation state of Co in complex, K3[Co(CO3)3] is +3. Hence, we have 

(Here carbonate anion is a bidentate ligand)

Hence the hybridisation involved is sp3d2 and the shape is octahedral.

Hence, the correct option is (b).

UPSEE: Important Questions and Preparation Tips – Solutions

Question 4:

Which of the following can exhibit geometrical isomerism?

(a) [MnBr4]2-

(b) [Pt(NH3)3Cl]+

(c) [PtCl2P(C2H5)3]2

(d) [Fe(H2O)5NO]2+

Solution 4:

The square planar complexes of the type [MA4] and [MA3B] and the octahedral complexes of the type [MA5B] do not show geometrical isomerism because in any of these cases, the possible spatial arrangements are equivalent. Therefore [MnBr4]2-, [Pt(NH3)3Cl]+ and [Fe(H2O)5NO]2+ complexes do not exhibit geometrical isomerism.

Hence, the correct option is (c).

UPSEE: Important Questions and Preparation Tips – Equilibrium

Question 5:

The correct IUPAC name of [Pt(NH3)2Cl2] is

(a) Diamminedichloridoplatinum (II)

(b) Diamminedichloridoplatinum (IV)

(c) Diamminedichloridoplatinum (0)

(d) Dichloridodiammineplatinum (IV)

Solution 5:

The complex compound is [Pt(NH3)2Cl2]. The ligands present in the compound are

(i) NH3 -neutral ligand represented as amine.

(ii) Cl-anion ligand (ending with-o-) represented as chlorido di prefixed to represent two ligands.

The oxidation number of platinum in the compound is 2. Hence, correct IUPAC name of [Pt (NH3)2Cl2] is

Diammine dichloridoplatinum (II).

Hence, the correct option is (a).

UPSEE: Important Questions and Preparation Tips – States of Matter

Question 6:

What kind of isomerism exists between [Cr(H2O)6]CL3 (violet) and [Cr(H2O)5Cl]Cl2 H2O (greyish-green)?

(a) Linkage isomerism

(b) Solvate isomerism

(c) Ionisation isomerism

(d) Coordination isomerism

Solution 6:

Solvate isomerism to shown when two compounds having same molecular formula differ by whether or solvent molecule is directly bonded to metal ion or is present as tree solvent molecules in the crystal lattice.

When water is present as solvent and show this type of isomerism then it is known as hydra-e isomerism.

Coordination compound [Cr(H2O)6]Cl3 and [Cr(H2O)5Cl]H2O.Cl2 are solvate isomers, because water is exchanged by chloride ion. This is why both of them show different colour on exposure to sunlight.

Hence, the correct option is (c).

Conclusion:

These notes will help students in understanding the concepts which are very important from the examination point of view like nomenclature of coordination compounds and valence bond theory. Students can practice the questions given here. Also, they can refer the given solutions if they stuck somewhere.

Ozonolysis: Alkene Reactions

Mathematics all chapters complete notes for UPSEE/UPTU 2018

Related Categories

Popular

View More