WBJEE 2015 Solved Mathematics Question Paper – Part 5

Find WBJEE 2015 Solved Mathematics Question Paper – Part 5 in this article. This paper consists of 10 questions (#41 to #50) from WBJEE 2015 Mathematics paper. Detailed solution of these questions has been provided so that students can match their solutions.

Importance of Previous Years’ Paper:

Previous years’ question papers help aspirants in understanding exam pattern, question format, important topics and assessing preparation. It has also been seen that sometimes questions are repeated in WBJEE Exam. So, this paper will certainly boost your confidence.

WBJEE is a common entrance examinations held at state level for admission to the Undergraduate Level Engineering and Medical courses in the State of West Bengal. The WBJEE engineering entrance exam has two sections – Mathematics, Physics and Chemistry. The Mathematics section of WBJEE 2015 engineering entrance exam consists of 80 questions.

WBJEE 2016 Solved Physics and Chemistry Question Paper

(A) 1                                      (B) 2

(C) 4                                      (D) 5

Sol.

Let the required point be (h, k)

The distance from the straight line x – 2y + 1 = 0

Any one of equations (1) combined with any one of equations (2) will yield 4 points.

44. The least value of 2x2 + y2 + 2xy + 2x – 3y + 8 for real numbers x and y is

(A) 2

(B) 8

(C) 3

(D) 1

Sol.

We have,

WBJEE Sample Question Paper Set-II

Sol.

A continuous function assuming only irrational value must be constant function.

(A) 1/3

(B) 1/9

(C) 1/81

(D) 0

Sol.

We have,

48. The variance of first 20 natural numbers is

(A) 133/4

(B) 279/12

(C) 133/2

(D) 399/4

Sol.

49. A fair coin is tossed a fixed number of times. If the probability of getting exactly 3 heads equals the probability of getting exactly 5 heads, then the probability of getting exactly one head is

(A) 1/64

(B) 1/32

(C) 1/16

(D) 1/8

Sol.

50. If the letters of the word PROBABILITY are written down at random in a row, the probability that two B-s are together is

(A) 2/11

(B) 10/11

(C) 3/11

(D) 6/11

Sol.

When two B’s are together it can be considered as one object.

So, total number of ways in which the letters of the word PROBABILITY are arranged such that that two

WBJEE 2016 Solved Mathematics Question Paper

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