WBJEE Solved Mathematics Question Paper 2015
It is very important to solve previous years’ papers before appearing for any engineering entrance examination. After solving previous years’ papers, students get an idea about the difficulty level, paper pattern and important topics.
In this article, engineering aspirants will get WBJEE Solved Mathematics Question Paper 2015. Students can score a maximum of 100 marks in this paper. 80 questions in this paper are divided into three categories, which will be based on distribution of different pattern of marking scheme.
Category 1
 This category consists of 60 questions (i.e. Q1 to Q60).
 Only one option is correct out of the four given options.
 For each correct response one mark is awarded, while 1/3 mark will be deducted for each incorrect answer.
 Marking more than one answer option in the OMR sheet will be treated as incorrect answer, which means 1/3 mark will be deducted.
Category 2
 This category consists of 15 questions (i.e. Q61 to Q75).
 Only one option is correct out of the four given options.
 Two marks will be awarded for each correct answer, while 2/3 marks will be deducted for each incorrect response.
 Marking more than one answer option in the OMR sheet will be treated as incorrect answer, which means 2/3 mark will be deducted.
Category 3
 This category consists of 5 questions (i.e. Q76 to Q80).
 One or more than one option is correct for each question.
 Each question carries two marks.
 Marking of correct options will lead to a maximum mark of two on pro rata basis.
 There is no negative marking for incorrect answer.
 Any marking of wrong option will lead to award of zero mark against the respective question – irrespective of the number of correct options marked.
Few sample questions from the Mathematics Question Paper are given below:
Question:
Let P(x) be a polynomial, which when divided by x – 3 and x – 5 leaves remainders 10 and 6 respectively. If the polynomial is divided by (x –3) (x–5) then the remainder is
(A) –2x + 16
(B) 16
(C) 2x – 16
(D) 60
Solution:
Let the remainder be ax + b
According to question,
P(x) = (x – 3)(x – 5) q(x) + (ax + b)
We have,
p(3) = 10
And p(5) = 6
Hence, the correct option is (a).
Question:
The letters of the word COCHIN are permuted and all the permutations are arranged in alphabetical order as in English dictionary. The number of words that appear before the word COCHIN is
(A) 360
(B) 192
(C) 96
(D) 48
Solution:
In dictionary the words starting from CC, CH, CI and CN will appear first
Now, fixing CC the remaining 4 letters O, H, I and N can be arranged in 4! ways.
Similarly the words starting from CH, CI and CN will also be arranged in 4! ways.
So, number of words that appear before the word COCHIN is (4!)4 = 96
Hence, the correct option is (C).
Question:
Let a, b, c, d be any four real numbers. Then a^{n} + b^{n} = c^{n} + d^{n} holds for any natural number n if
(A) a + b = c + d
(B) a – b = c – d
(C) a + b = c + d, a^{2} + b^{2} = c^{2} + d^{2}
(D) a – b = c – d, a^{2} – b^{2} = c^{2} – d^{2}
Solution:
Put n = 1, a + b = c + d ...... (1)
Put n = 3, a^{3} + b^{3} = c^{3} + d^{3} ........... (2)
from (1) and (2) ab = cd
Consider a quadratic with roots (a^{3}, b^{3})
x^{2} – (a^{3} + b^{3})x + a^{3}b^{3} = 0 ........ (3)
Consider another quadratic with roots (c^{3}, d^{3})
x^{2} – (c^{3} + d^{3})x + (cd)^{3} = 0 ................. (4)
Since a^{3} + b^{3} = c^{3} + d^{3} and (cd)^{3} = (ab)^{3}
Both quadratic are same and quadratic cannot have more than 2 roots.
Here, a = c and b = d or a = d, b = c
Hence, the correct option is (D).
Students can use the links given below to view solved question paper of Mathematics.
Solved Mathematics Question Paper 

Conclusion:
Students can easily get an idea about the difficulty level, paper pattern and important topics with the help of previous years’ papers help. So, it is very important for students to go through the previous years’ papers before appearing for any engineering entrance examination.